10=x^2+0.06x

Solution for 10=x^2+0.06x equation:

10=x^2+0.06x

We move all terms to the left:

10-(x^2+0.06x)=0

We get rid of parentheses

-x^2-0.06x+10=0

We add all the numbers together, and all the variables

-1x^2-0.06x+10=0

a = -1; b = -0.06; c = +10;
Δ = b2-4ac
Δ = -0.062-4·(-1)·10
Δ = 40.0036
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.06)-\sqrt{40.0036}}{2*-1}=\frac{0.06-\sqrt{40.0036}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.06)+\sqrt{40.0036}}{2*-1}=\frac{0.06+\sqrt{40.0036}}{-2}
$